4(x^2+6)=35x=0

Solution for 4(x^2+6)=35x=0 equation:

4(x^2+6)=35x=0

We move all terms to the left:

4(x^2+6)-(35x)=0

We add all the numbers together, and all the variables

-35x+4(x^2+6)=0

We multiply parentheses

4x^2-35x+24=0

a = 4; b = -35; c = +24;
Δ = b2-4ac
Δ = -352-4·4·24
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-29}{2*4}=\frac{6}{8}
=3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+29}{2*4}=\frac{64}{8}
=8
$